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9x^2=30x+25=11
We move all terms to the left:
9x^2-(30x+25)=0
We get rid of parentheses
9x^2-30x-25=0
a = 9; b = -30; c = -25;
Δ = b2-4ac
Δ = -302-4·9·(-25)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30\sqrt{2}}{2*9}=\frac{30-30\sqrt{2}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30\sqrt{2}}{2*9}=\frac{30+30\sqrt{2}}{18} $
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